| ⇦ | 
| ⇨ |
Two parallel metal plates having charges +Q and -Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will
Options
(a) remain same
(b) become zero
(c) increases
(d) decrease
Correct Answer:
decrease
Explanation:
Electric field E = σ / ? = Q / A?
? of kerosine oil is more than that of air. As ? increases, E decreases.
Related Questions: - A wire of length L metre carrying a current I ampere is bent in the form
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- If an electron and a positron annihilate, the energy released is
- A parallel plate air capacitor has capacity C, distance of seperation between plate
- The velocity of sound is V, in air. If the density of air is increased to four times
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of length L metre carrying a current I ampere is bent in the form
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- If an electron and a positron annihilate, the energy released is
- A parallel plate air capacitor has capacity C, distance of seperation between plate
- The velocity of sound is V, in air. If the density of air is increased to four times
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply