| ⇦ |
| ⇨ |
Two parallel metal plates having charges +Q and -Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will
Options
(a) remain same
(b) become zero
(c) increases
(d) decrease
Correct Answer:
decrease
Explanation:
Electric field E = σ / ? = Q / A?
? of kerosine oil is more than that of air. As ? increases, E decreases.
Related Questions: - When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- The unit of thermal conductivity is
- At what distance from the centre of earth, the value of acceleration due to gravity
- The unit of permitivity of free space, ε₀ is
- A stone falls freely under gravity.It covers distances h₁,h₂ and h₃
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- The unit of thermal conductivity is
- At what distance from the centre of earth, the value of acceleration due to gravity
- The unit of permitivity of free space, ε₀ is
- A stone falls freely under gravity.It covers distances h₁,h₂ and h₃
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply