| ⇦ | 
| ⇨ |
Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C and 5 x 10⁻² C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is:
Options
(a) 2 x 10⁻² C
(b) 3 x 10⁻² C
(c) 4 x 10⁻² C
(d) 1 x 10⁻² C
Correct Answer:
3 x 10⁻² C
Explanation:
At equilibrium potential of both sphere becomes same if charge of sphere one x where Q= 4 x 10 10⁻² C
v₁ = v₂ kx / 1cm = k(Q – x) / 3 cm
3x = Q – x 4x = Q
x = Q/4 = 4 x 10⁻² / 4 C = 1 x 10⁻²
Q’ = Q – x = 3 x 10⁻² C
Related Questions:
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- When photons of energy hν fall on an aluminium plate (of work function E₀),
- Wires A and B are made from the same material. A has twice the diameter and three times
- The drift speed of electrons in copper wire of diameter and length l is v.
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply