| ⇦ |
| ⇨ |
Two closed organ pipes when sounded simultaneously give 4 beats/second. If longer pipe has a length of 1m, then length of shorter pipe will be (v=300 m/s)
Options
(a) 185.5 cm
(b) 94.9 cm
(c) 90 cm
(d) 80 cm
Correct Answer:
94.9 cm
Explanation:
n₂ – n₁ = 4, For closed pipe, n = V/4l
(V/4l₂) – (V/4l₁) = 4 ⇒ (V/4l₂) – (V/4×1) = 4
(300/4l₂) – (300/4) = 4 ⇒ 75/l₂ = 4 + 75 ⇒ 75/l₂ = 79
⇒ l₂ = (75/79) met = (75×100)/79 = 94.9 cm.
Related Questions: - A body is under stress F and has Young’s modulus Y, then the energy
- Which of the following will be σ if Y=2.4 η?
- A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- Dimensions [ML⁻¹T⁻¹] are related with
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body is under stress F and has Young’s modulus Y, then the energy
- Which of the following will be σ if Y=2.4 η?
- A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- Dimensions [ML⁻¹T⁻¹] are related with
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply