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Two closed organ pipes when sounded simultaneously give 4 beats/second. If longer pipe has a length of 1m, then length of shorter pipe will be (v=300 m/s)
Options
(a) 185.5 cm
(b) 94.9 cm
(c) 90 cm
(d) 80 cm
Correct Answer:
94.9 cm
Explanation:
n₂ – n₁ = 4, For closed pipe, n = V/4l
(V/4l₂) – (V/4l₁) = 4 ⇒ (V/4l₂) – (V/4×1) = 4
(300/4l₂) – (300/4) = 4 ⇒ 75/l₂ = 4 + 75 ⇒ 75/l₂ = 79
⇒ l₂ = (75/79) met = (75×100)/79 = 94.9 cm.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moving in a straight line covers half the distance with speed of 3 m/s
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- A black body at a temperature of 227⁰C radiates heat at a rate of 20 cal m⁻²s⁻¹.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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