Two closed organ pipes when sounded simultaneously give 4 beats/second.

Two Closed Organ Pipes When Sounded Simultaneously Give 4 Beatssecond Physics Question

Two closed organ pipes when sounded simultaneously give 4 beats/second. If longer pipe has a length of 1m, then length of shorter pipe will be (v=300 m/s)

Options

(a) 185.5 cm
(b) 94.9 cm
(c) 90 cm
(d) 80 cm

Correct Answer:

94.9 cm

Explanation:

n₂ – n₁ = 4, For closed pipe, n = V/4l
(V/4l₂) – (V/4l₁) = 4 ⇒ (V/4l₂) – (V/4×1) = 4
(300/4l₂) – (300/4) = 4 ⇒ 75/l₂ = 4 + 75 ⇒ 75/l₂ = 79
⇒ l₂ = (75/79) met = (75×100)/79 = 94.9 cm.

Related Questions:

  1. Which of the following, is a vector quantity?
  2. Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
  3. A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
  4. If R is the radius of the earth and g is the acceleration due to gravity
  5. The maximum kinetic energy of emitted electrons in a photoelectric effect

Topics: Waves (80)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*