| ⇦ | 
| ⇨ |
Two bulbs when connected in parallel to a source take 60W each, the power consumed, when they are connected in series with the same source is
Options
(a) 15W
(b) 30W
(c) 60W
(d) 120W
Correct Answer:
30W
Explanation:
In series, P = P₁P₂ / P₁+P₂
Given: P₁ = P₂ = 60
Therefore, Power P = (60 × 60) / (60 × 60) = 30 W.
Related Questions: - The limiting angle of incidence for an optical ray that can be transmitted
- A 120 m long train is moving in a direction with speed 20 m/s.A train B moving
- What is the wavelength of light for the least energetic photon emitted
- When a radioactive substance emits an ∝ particle, its position in the periodic table
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The limiting angle of incidence for an optical ray that can be transmitted
- A 120 m long train is moving in a direction with speed 20 m/s.A train B moving
- What is the wavelength of light for the least energetic photon emitted
- When a radioactive substance emits an ∝ particle, its position in the periodic table
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply