| ⇦ | 
| ⇨ |
Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart.They are then allowed to move towards each other under mutual gravitational attraction with the escape velocity .Their relative velocity of approach at a separation distance r between them is
Options
(a) [2 G(m₁- m₂ )/r]¹/²
(b) [2 G(m₁+m₂ )/r]¹/²
(c) [r/2G(m₁m₂)]¹/²
(d) [2G / r(m₁m₂)]¹/²
Correct Answer:
[2 G(m₁+m₂ )/r]¹/²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The masses of two radioactive substances are same and their half lives
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- If white light is used in Young’s double slit experiment
- Consider the following two statements about Kirchhoff’s law
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The masses of two radioactive substances are same and their half lives
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- If white light is used in Young’s double slit experiment
- Consider the following two statements about Kirchhoff’s law
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply