| ⇦ |
| ⇨ |
Two balls are dropped from same height at 1 second interval of time. The seperation between the two balls after 3 second of the drop of the 1st ball is
Options
(a) 50 m
(b) 40 m
(c) 35 m
(d) 25 m
Correct Answer:
25 m
Explanation:
For the motion of ball is, u=0, a=g, t = 3s.
Using the kinematic equation S=ut+1/2 at².
Let S₁ is the distance covered by the first ball in 3 sec.
.·. S₁=0+1/2x10x(3)²=45 m
Let S₂ is the distance covered by the second ball is 2 sec.
.·. S₂=0+1/2x10x(2)²=20 m
Separation between the two ball is = S₁-S₂
= 45-20 = 25 m .
Related Questions: - A body starts from rest with an acceleration of 2 m/s². After 5 second,
- The time period of bar magnet is doubled when magnetic field is reduced
- If the focal length of a concave mirror is 50 cm, then where should the object
- Dimensions of Torque are
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body starts from rest with an acceleration of 2 m/s². After 5 second,
- The time period of bar magnet is doubled when magnetic field is reduced
- If the focal length of a concave mirror is 50 cm, then where should the object
- Dimensions of Torque are
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply