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Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series to a voltage source of 100V. The charge on 15 μF is
Options
(a) 500 μC
(b) 100 μC
(c) 200 μC
(d) 280 μC
Correct Answer:
200 μC
Explanation:
Equivalent capacitance = C
1/C = 1/3 + 1/10 + 1/15 = (10 + 3 + 2) / 30 = 15 / 30 = 1 / 2
⇒ C = 2 μF
Charge through each capacitor is same as they are joined in series.
Q = CV = 2 × 100 = 200 μC
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- P-type semiconductors are made by adding impurity element
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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