| ⇦ |
| ⇨ |
The weight of a body on surface of earth is 12.6 N. When it is raised to a height half the radius of earth its weight will be
Options
(a) 2.8 N
(b) 5.6 N
(c) 12.6 N
(d) 25.2 N
Correct Answer:
5.6 N
Explanation:
Weight of body on the surface of earth, mg=12.6 N
At height h, the value of g’ is given by
g’=g (R/R+(R/2))²
=g 4/9
Weight at height, h=mg 4/9
h=12.6×4/9 =5.6 N
Related Questions: - Two radiations of photons energies 1 eV and 2.5 eV, successively
- If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
- A particle of mass m executes simple harmonic motion with amplitude
- When 4 A current flows for 2 min in an electroplating experiment,
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
- A particle of mass m executes simple harmonic motion with amplitude
- When 4 A current flows for 2 min in an electroplating experiment,
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply