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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
Related Questions: - The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- Two balls are dropped from same height at 1 second interval of time.
- Wb/m² is equal to
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- A stone thrown into still water, creates a circular wave pattern moving radially
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- Two balls are dropped from same height at 1 second interval of time.
- Wb/m² is equal to
- The breaking stress of a wire depends upon
- A stone thrown into still water, creates a circular wave pattern moving radially
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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