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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- If vectors A=cos wti + sin wtj and B= cos wt/2 i + sin wt/2 j are functions of time,
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
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- An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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