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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- The kinetic energy of an electron in the first excited state is
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- The distance travelled by a particle starting from rest and moving
- A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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