The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters

⇦

⇨

The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters and t in second is a wave travelling along the:

Options

(a) negative x direction with frequency 1 Hz.
(b) positive x direction with frequency π Hz and wavelength λ = 0.2 m.
(c) positive x direction with frequency 1 Hz and wavelength λ = 0.2 m.
(d) negative x direction with amplitude 0.25 m and wavelength λ = 0.2 m.

Correct Answer:

positive x direction with frequency 1 Hz and wavelength λ = 0.2 m.

Explanation:

y = 0.25 sin (10 2πx – 2πt) Comparing this equation with the standard wave equation
y = a sin (kx – ?t) We get, k = 10π
⇒ 2π / λ = 10π ⇒ λ = 0.2 m.
? = 2π or, 2πv = 2π ⇒ v = 1 Hz.
The sign insider the bracket is negative, hence the wave travels in +ve x-direction.

Related Questions:

1. The horizontal range and maximum height of a projectile are equal.The angle of projection
2. If a spring of spring constant k stretched by a length x under tension T, the energy
3. A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
4. A series R-C circuit is connected to an alternating voltage source. Consider two
5. A scooter is going round a circular road of radius 100 m at a speed of 10m/s

Topics: Waves (80)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends