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The velocity of molecules of a gas at temperature 120 K is v. At what temperature will the velocity be 2v?
Options
(a) 120 K
(b) 240 K
(c) 480 K
(d) 1120 K
Correct Answer:
480 K
Explanation:
[ʋ(rms)]² ∝ absolute temperature
[ʋ₂ / ʋ₁]² = T₂ / T₁ ⇒ (2V / V)² = T₂ / 120
.·. T₂ = 120 × 4 = 480 K
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
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