| ⇦ | 
| ⇨ |
The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, dQ/dt through the rod in a steady state is given by:
Options
(a) dQ/dt = k(T₁ – T₂) / LA
(b) dQ/dt = kLA (T₁ – T₂)
(c) dQ/dt = kA (T₁ – T₂) / L
(d) dQ/dt = kL (T₁ – T₂) / A
Correct Answer:
dQ/dt = kA (T₁ – T₂) / L
Explanation:
dQ / dt = kA (T₁ -T₂) / L
[(T₁ -T₂) is the temperature difference]
Related Questions: - In one dimensionsal motion,instantaneous speed v statisfies 0⦤v⦤vₒ
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- The sun light reaches us as white and not as its components because
- Find the maximum velocity with which a train can be moved on a circular track
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In one dimensionsal motion,instantaneous speed v statisfies 0⦤v⦤vₒ
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- The sun light reaches us as white and not as its components because
- Find the maximum velocity with which a train can be moved on a circular track
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply