| ⇦ | 
| ⇨ |
The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, dQ/dt through the rod in a steady state is given by:
Options
(a) dQ/dt = k(T₁ – T₂) / LA
(b) dQ/dt = kLA (T₁ – T₂)
(c) dQ/dt = kA (T₁ – T₂) / L
(d) dQ/dt = kL (T₁ – T₂) / A
Correct Answer:
dQ/dt = kA (T₁ – T₂) / L
Explanation:
dQ / dt = kA (T₁ -T₂) / L
[(T₁ -T₂) is the temperature difference]
Related Questions: - For a particle in a non-uniform accelerated circular motion correct statement is
- The horizontal range and the maximum height of a projectile are equal
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
- If threshold wevelength for sodium is 6800 Å, the work function will be
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a particle in a non-uniform accelerated circular motion correct statement is
- The horizontal range and the maximum height of a projectile are equal
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
- If threshold wevelength for sodium is 6800 Å, the work function will be
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply