| ⇦ | 
| ⇨ |
The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- Find out the angle of projection, if range is 4 times of maximum height
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- If force(F),velocity(v) and time(T) are taken as units, then the dimensions of mass are
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- Find out the angle of projection, if range is 4 times of maximum height
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- If force(F),velocity(v) and time(T) are taken as units, then the dimensions of mass are
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply