| ⇦ | 
| ⇨ |
The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - The dimensions of Planck’s constant is same as that of
- Coherent sources are those sources for which
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- B is doped in Si or Ge, then we will get
- The horizontal range and maximum height of a projectile are equal.The angle of projection
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimensions of Planck’s constant is same as that of
- Coherent sources are those sources for which
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- B is doped in Si or Ge, then we will get
- The horizontal range and maximum height of a projectile are equal.The angle of projection
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply