| ⇦ | 
| ⇨ |
The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- A rocket is fired upward from the earth surface such that it creates an acceleration
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- A rocket is fired upward from the earth surface such that it creates an acceleration
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply