| ⇦ | 
| ⇨ |
The total energy of a simple harmonic oscillator is proportional to
Options
(a) square root of displacement
(b) velocity
(c) frequency
(d) square of amplitude
Correct Answer:
square of amplitude
Explanation:
The total energy of a simple harmonic oscillator
(1/2). mω²A² (or) (1/2). kA²
Therefore it is proportional to the square of the amplitude.
Related Questions: - A coil has an area of 0.05 m² and it has 800 turns. It is placed perpendicularly
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- The distance travelled by an object along a straight line in time t is given by
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coil has an area of 0.05 m² and it has 800 turns. It is placed perpendicularly
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- The distance travelled by an object along a straight line in time t is given by
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply