| ⇦ |
| ⇨ |
The total energy of a simple harmonic oscillator is proportional to
Options
(a) square root of displacement
(b) velocity
(c) frequency
(d) square of amplitude
Correct Answer:
square of amplitude
Explanation:
The total energy of a simple harmonic oscillator
(1/2). mω²A² (or) (1/2). kA²
Therefore it is proportional to the square of the amplitude.
Related Questions: - The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- The temperature of ideal gas is reduced from 927° C to 27° C. The r.m.s velocity
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- The temperature of ideal gas is reduced from 927° C to 27° C. The r.m.s velocity
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply