| ⇦ | 
| ⇨ |
The total energy of a particle executing SHM is 80 J. What is the potential energy when the particle is at a distance of 3/4 of amplitude from mean position
Options
(a) 60 J
(b) 10 J
(c) 40 J
(d) 45 J
Correct Answer:
45 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- The horizontal range and the maximum height of a projectile are equal
- The valence band and the conductance band of a solid overlap at low temperature
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- The horizontal range and the maximum height of a projectile are equal
- The valence band and the conductance band of a solid overlap at low temperature
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
U = 80 sin2 x sin-3/4
= 80 x 9
————–
16
=45 J