| ⇦ | 
| ⇨ |
The time period of a thin bar magnet in Earth’s magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be
Options
(a) T / 2
(b) T
(c) √2T
(d) 2T
Correct Answer:
2T
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Ohm’s law is not applicable except to
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- A luminous object is seperated from a screen by distance d. A convex lens
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ohm’s law is not applicable except to
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- A luminous object is seperated from a screen by distance d. A convex lens
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply