| ⇦ | 
| ⇨ |
The time period of a thin bar magnet in Earth’s magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be
Options
(a) T / 2
(b) T
(c) √2T
(d) 2T
Correct Answer:
2T
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- MA⁻¹T⁻² is the dimensional formula of
- A ball is dropped from a high rise platform at t = 0 starting from rest
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A wheel has moment of inertia 5 x 10⁻³ kgm² and is making 20 revolutions per sec
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- MA⁻¹T⁻² is the dimensional formula of
- A ball is dropped from a high rise platform at t = 0 starting from rest
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A wheel has moment of inertia 5 x 10⁻³ kgm² and is making 20 revolutions per sec
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply