| ⇦ |
| ⇨ |
Aperture of human eye is 0.2 cm. The minimum magnifying power of a visual telescope, whose objective has diameter 100 cm is
Options
(a) 500
(b) 0.002
(c) 0.02
(d) 100
Correct Answer:
500
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In nuclear fusion, two nuclei come together to form a large nucleus.
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- The dimensions of latent heat are
- A galvanometer has a resistance 50Ω. A resistance of 5Ω is connected parallel to it.
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In nuclear fusion, two nuclei come together to form a large nucleus.
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- The dimensions of latent heat are
- A galvanometer has a resistance 50Ω. A resistance of 5Ω is connected parallel to it.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply