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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Laser beams are used to measure long distance because
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- The molar specific heats of an ideal gas at constant pressure and volume are denoted
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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