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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two positive ions, each carrying a charge q, are separated by a distance d
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- A block of mass M is attached to the lower end of a vertical spring
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- A glass flask weighing 390 g having internal volume 500 cc just floats
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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