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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A plane wave of wavelength 6250Å is incident normally on a slit of width 2×10⁻² cm.
- Photon of frequency ν has a momentum associated with it. If c is the velocity
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
- Identify the paramagnetic substance
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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