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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
Related Questions: - The ratio of the numerical value of the average velocity and average speed
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
- In the experiment for determination of velocity of sound in air,
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the numerical value of the average velocity and average speed
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
- In the experiment for determination of velocity of sound in air,
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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