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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- Time period of the rotation of the earth about its own axis is 24 hour
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a spring is extended by 2 cm energy stored is 100 J. When extended further by 2 cm
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- Time period of the rotation of the earth about its own axis is 24 hour
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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