| ⇦ | 
| ⇨ |
The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference θ in ⁰C between the two junctions according to the relation
E = 30θ – θ² / 15
The neutral temperature for the thermocouple will be
Options
(a) 30⁰C
(b) 450⁰C
(c) 400⁰C
(d) 225⁰C
Correct Answer:
225⁰C
Explanation:
E = 30θ – θ² / 15
For neutral temperature, dE/ dθ = 0
0 = 30 – 2/15 . θ
θ = 15 x 15
= 225⁰C
Related Questions: - The core of a transformer is laminated because
- The sum of the magnitudes of two forces acting at a point is 16 N
- For non-conductors, the energy gap is
- A particle executes simple harmonic oscillations with an amplitude
- If the length of a stretched string is shortened by 4% and the tension is increased
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The core of a transformer is laminated because
- The sum of the magnitudes of two forces acting at a point is 16 N
- For non-conductors, the energy gap is
- A particle executes simple harmonic oscillations with an amplitude
- If the length of a stretched string is shortened by 4% and the tension is increased
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply