| ⇦ | 
| ⇨ |
The standard emf for the cell reaction, 2Cu⁺(aq) → Cu(s) + Cu²⁺(aq) is +0.36 V at 298 K. The equilibrium constant of the reaction is
Options
(a) 5 ˣ 10⁶
(b) 1.4 ˣ 10¹²
(c) 7.4 ˣ 10¹²
(d) 1.2 ˣ 10⁶
Correct Answer:
1.2 ˣ 10⁶
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - At 27⁰C average kinetic energy of one mole of helium gas can be given
- 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
- Equivalent conductances of Ba²⁺ and Cl⁻ ions are 127 and 76 ohm⁻¹ cm⁻¹ eq⁻¹
- If the dispersed phase is a liquid and the dispersion medium is solid,the colloid
- The complex [CoF₆]⁴⁻ is
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At 27⁰C average kinetic energy of one mole of helium gas can be given
- 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
- Equivalent conductances of Ba²⁺ and Cl⁻ ions are 127 and 76 ohm⁻¹ cm⁻¹ eq⁻¹
- If the dispersed phase is a liquid and the dispersion medium is solid,the colloid
- The complex [CoF₆]⁴⁻ is
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
In equilibrium,
(E)cell=0
So, (E°)cell=(0.0591/2)logK
=> (0.36×2)÷0.0591=logK
=> logK=12.18
=> K=1.51×10^12