| ⇦ |
| ⇨ |
The standard emf for the cell reaction, 2Cu⁺(aq) → Cu(s) + Cu²⁺(aq) is +0.36 V at 298 K. The equilibrium constant of the reaction is
Options
(a) 5 ˣ 10⁶
(b) 1.4 ˣ 10¹²
(c) 7.4 ˣ 10¹²
(d) 1.2 ˣ 10⁶
Correct Answer:
1.2 ˣ 10⁶
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following shows maximum number of oxidation states
- Oxygen is not evolved on reaction of ozone with
- In which of the following hydrocarbons, hydrogen is most acidic
- XeF₂ is isostructural with:
- A gas decolourised by KMnO₄ solution but gives no precipitate with ammoniacal cuprous
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following shows maximum number of oxidation states
- Oxygen is not evolved on reaction of ozone with
- In which of the following hydrocarbons, hydrogen is most acidic
- XeF₂ is isostructural with:
- A gas decolourised by KMnO₄ solution but gives no precipitate with ammoniacal cuprous
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

In equilibrium,
(E)cell=0
So, (E°)cell=(0.0591/2)logK
=> (0.36×2)÷0.0591=logK
=> logK=12.18
=> K=1.51×10^12