| ⇦ |
| ⇨ |
The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle will be
Options
(a) 9.6 x 10⁷ C kg⁻¹
(b) 19.2 x 10⁷ C kg⁻¹
(c) 4.8 x 10⁷ C kg⁻¹
(d) 2.4 x 10⁷ C kg⁻¹
Correct Answer:
4.8 x 10⁷ C kg⁻¹
Explanation:
For proton, specific charge = e / m = 9.6 × 10⁷ C kg⁻¹
For alpha particle, specific charge = 2e / 4m = 1e / 2m
= (1/2) × 9.6 × 10⁷ = 4.8 × 10⁷ C kg⁻¹
Related Questions: - A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
- Which of the following combinations should be selected for better tuning of an L-C-R
- The phenomenon of radioactivity
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
- Which of the following combinations should be selected for better tuning of an L-C-R
- The phenomenon of radioactivity
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply