| ⇦ | 
| ⇨ |
The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is
Options
(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴
Correct Answer:
2 ˣ 10⁻⁴
Explanation:
K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻
K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.
Related Questions: - Which of the following species is not electrophilic in nature
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- Carbon and silicon belong to (IV) group.The maximum coordination number
- Which one of the following is a false statement
- Which of the following will not act as a buffer?
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following species is not electrophilic in nature
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- Carbon and silicon belong to (IV) group.The maximum coordination number
- Which one of the following is a false statement
- Which of the following will not act as a buffer?
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply