| ⇦ | 
| ⇨ |
The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is
Options
(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴
Correct Answer:
2 ˣ 10⁻⁴
Explanation:
K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻
K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.
Related Questions: - Oxidation number of iodine in IO₃⁻, IO₄⁻, KI and I₂ respectively are
- A flask contains 36% oxtgen and 26% hydrogen. If the total pressure of the mixture
- One of the oxidants used with liquid propellants is
- Ozone is formed in the upper atmosphere from oxygen by the action of
- A vessel contains a mixture of different types of gases.Which of the following
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oxidation number of iodine in IO₃⁻, IO₄⁻, KI and I₂ respectively are
- A flask contains 36% oxtgen and 26% hydrogen. If the total pressure of the mixture
- One of the oxidants used with liquid propellants is
- Ozone is formed in the upper atmosphere from oxygen by the action of
- A vessel contains a mixture of different types of gases.Which of the following
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply