| ⇦ | 
| ⇨ |
The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is
Options
(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴
Correct Answer:
2 ˣ 10⁻⁴
Explanation:
K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻
K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.
Related Questions: - The oxidation number of phosphorus and basicity of acid in pyrophosphoric acid
- In the aluminothermite process , aluminium acts as
- A hydrocarbon contains 20% hydrogen and 80% carbon.The empirical formula is
- Oxidation number of carbon in CH₂Cl₂ is
- Which of the following has the minimum bond length ?
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oxidation number of phosphorus and basicity of acid in pyrophosphoric acid
- In the aluminothermite process , aluminium acts as
- A hydrocarbon contains 20% hydrogen and 80% carbon.The empirical formula is
- Oxidation number of carbon in CH₂Cl₂ is
- Which of the following has the minimum bond length ?
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply