| ⇦ |
| ⇨ |
The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is
Options
(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴
Correct Answer:
2 ˣ 10⁻⁴
Explanation:
K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻
K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.
Related Questions: - which one doesn’t liberate NH₃ when undergoes hydrolysis
- Amines behave as
- Average molar kinetic energy of CO and N₂ at same temperature is
- ΔH°f (298 K) of methanol is given by the chemical equation
- For the reaction 2SO₃(g) → 2SO₂(g) + O₂(g) the entropy change (ΔG) is
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- which one doesn’t liberate NH₃ when undergoes hydrolysis
- Amines behave as
- Average molar kinetic energy of CO and N₂ at same temperature is
- ΔH°f (298 K) of methanol is given by the chemical equation
- For the reaction 2SO₃(g) → 2SO₂(g) + O₂(g) the entropy change (ΔG) is
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply