The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.

⇦

⇨

The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is

Options

(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴

Correct Answer:

2 ˣ 10⁻⁴

Explanation:

K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻

K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.

Related Questions:

1. In tetragonal crystal system, which of following is not true
2. The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
3. Which of the following species has four lone pairs of electrons?
4. Which would exhibit ionisation isomerism
5. Which of the following will not be soluble in sodium hydrogen carbonate

Topics: Equilibrium (104)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends