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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- Potentiometer measures the potential difference more accurately than a voltmeter
- Before using the tangent galvanometer, its coil is set in
- A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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