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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body cools in 7 minute from 60⁰C to 40⁰C. What time, in minute does it take to cool
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- Given A=4i+6j and B=2i+3j. Which of the following is correct?
- The turn ratio of a transformer is 1:2. An electrolytic dc cell of emf 2 volt is connected
- In a coil having e.m.f. of 8 V induced for 0.05 s. The value of current changes
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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