⇦ | ⇨ |
The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- what is the de-Broglie wavelength of the electron accelerated through a potential
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- Consider two nuclei of the same radioactive nuclide. One of the nuclei was created
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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