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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of 3 wires of same metal are in the ratio 1:2:3 and their lengths
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- A particle executes simple harmonic oscillations with an amplitude
- The maximum kinetic energy of the photoelectrons depends only on
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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