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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T.
- Find the maximum velocity with which a train can be moved on a circular track
- A body revolved around the sun 27 times faster than the earth. What is the ratio
- Two tuning forks are sounded together and produce 2 beats per second.
- A galvanometer acting as a voltmeter will have
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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