The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.

The Root Mean Square Speed Of Oxygen Molecule O At Physics Question

The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be

Options

(a) v
(b) √2 v
(c) 2v
(d) 2√2 v

Correct Answer:

2v

Explanation:

The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v

Related Questions:

  1. The resistance of a carbon resistor of colour code Red-Red Green Silver is(in kΩ)
  2. A wire mesh consisting of very small squares is viewed at a distance
  3. If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
  4. The given graph represents V-I characteristic for a semiconductor device
  5. A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery

Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*