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The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - α-particles, deuterons and protons of same energy are moving in a perpendicular
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
- The angle between the vectors (i+j) and (j+k) is
- In which case positive work has to be done in seperating them?
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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