| ⇦ | 
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
- A particle moves in a circle of radius 5 cm with constant speed and time period
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- The position vector of a particle R as a function of time is given by
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
- A particle moves in a circle of radius 5 cm with constant speed and time period
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- The position vector of a particle R as a function of time is given by
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply