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The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Identify the wrong statement
- A particle executes simple harmonic oscillations with an amplitude
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- Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
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Topics: Behavior of Perfect Gas and Kinetic Theory (34)
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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