| ⇦ | 
| ⇨ |
The resistance of a carbon resistor of colour code Red-Red Green Silver is (in kΩ)
Options
(a) 2200±5%
(b) 2200±10%
(c) 220±10%
(d) 220±5%
Correct Answer:
2200±10%
Explanation:
Given, Colour coding of resistance = Red, Red, Green, Silver
First band value = 2
Second band value = 2
Third band value = 10⁵
Fourth band value = ± 10%
Now, R = 22 × 10⁵ ± 10% Ω
R = 2200 ± 10% kΩ
Related Questions: - If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- A gaussian sphere encloses an electric dipole within it. The total flux
- Function of a rectifier is
- A thin wire of resistance 4 ohm is bent to form a circle. The resistance across
- Work done by an external agent in separating the parallel plate capacitor is
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- A gaussian sphere encloses an electric dipole within it. The total flux
- Function of a rectifier is
- A thin wire of resistance 4 ohm is bent to form a circle. The resistance across
- Work done by an external agent in separating the parallel plate capacitor is
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply