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The ratio of the difference in energy between first and second Bohr orbit to that between the second and the third Bohr orbit is
Options
(a) 1/2
(b) 1/3
(c) 4/9
(d) 27/5
Correct Answer:
27/5
Explanation:
E₁ – E₂ = 1312 x Z²(1/1² – 1/2²)
= 1312 x Z²(3/4)
E₂ – E₃ = 1312 x Z²(1/2² – 1/3²)
= 1312 x Z²(5/36)
From eqs. (i) and (ii)
E₁ – E₂ / E₂ – E₃ = 3 x 26 / 4 x 5 = 27/5
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Question Type: Memory
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Difficulty Level: Easy
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Topics: Structure of Atom
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Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bivalent metal has the equivalent weight of 12. The molecular weight
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- The hybridisation of C₂H₂ is
- At 0K, (i) ¹²C and (ii) a mixture of ¹²C and ¹⁴C will
- Which of the following possesses highest melting point
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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