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In an organic compound phosphorus is estimated as
Options
(a) Mg₂P₂O₇
(b) Mg₃(PO₄)₂
(c) H₃PO₄
(d) P₂O₅
Correct Answer:
Mg₂P₂O₇
Explanation:
A pre-weighed amount of organic compound is heated with concentrated nitric acid (HNO₃) in a tube. Phosphorus present in the compound gets converted into phosphoric acid. Now the content of tube are heated with magnesium mixture i.e MgSO₄ + NH₄Cl + NH₄OH, so that magnesium ammonium phosphate MgNH₄PO₄ is formed which is collected, washed, dried and ignited to get magnesium pyrophosphate Mg₂ P₂O₇, which is then weighed. H₃PO₄ → MgNH₄PO₄ + 3HCl(Magnesium ammonium phosphate (white ppt.). 2MgNH₄PO₄ → Mg₂P₂O₇ ↓ + 2NH₃ + H₂O. Knowing the weight of Mg₂P₂O₇, percentage of phosphorus can be calculated.
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Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Standard electrode potential for Sn⁴⁺/Sn²⁺ couple is +0.15 V and that for the
- Cresol is
- The trivial names of propanone and 3-methyl-2-butanone are
- What is the magnetic moment for Mn²⁺ ion in low spin state
- When phenol reacts with phthalic anhydride in presence of H₂SO₄ and heated
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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