| ⇦ | 
| ⇨ |
The ratio of longest wavelength corresponding to Lyman and Blamer series in hydrogen spectrum is
Options
(a) 3 / 23
(b) 7 / 29
(c) 9 / 13
(d) 5 / 27
Correct Answer:
5 / 27
Explanation:
For Lyman series (2 → 1)
1/λL = R [1 – 1/2] = 3R/4
For Balmer series (3 → 2)
1/λB = R [1/4 – 1/9] = 5R/36
λL / λB = 4/3R / 36/5R = 4/36 (5/3) = 5/27
Related Questions: - A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- At the first minimum adjacent to the central maximum of a single-slit diffraction
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
- A body is thrown vertically up with a velocity u.It passes three points A,B and C
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- At the first minimum adjacent to the central maximum of a single-slit diffraction
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
- A body is thrown vertically up with a velocity u.It passes three points A,B and C
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply