| ⇦ | 
| ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - A body initially at rest is moving with uniform acceleration a m/s²
- Energy of photon whose frequency is 10¹² MHz will be
- Energy in a current carrying coil is stored in the form of
- A circular disc X of radius R is made from an iron plate of thickness t and another disc
- A block of mass m1 rests on a horizontal table. A light string connected
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body initially at rest is moving with uniform acceleration a m/s²
- Energy of photon whose frequency is 10¹² MHz will be
- Energy in a current carrying coil is stored in the form of
- A circular disc X of radius R is made from an iron plate of thickness t and another disc
- A block of mass m1 rests on a horizontal table. A light string connected
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm