| ⇦ | 
| ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - A particle has initial velocity(3i⃗ +4j⃗)and has acceleration (0.4i⃗ +0.3j⃗)
- The numebr 0 (zero) is required for
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- An electron moving in a uniform magnetic field of induction of intensity B,
- A ballon rises from rest with a constant acceleration g/8. A stone is released
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle has initial velocity(3i⃗ +4j⃗)and has acceleration (0.4i⃗ +0.3j⃗)
- The numebr 0 (zero) is required for
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- An electron moving in a uniform magnetic field of induction of intensity B,
- A ballon rises from rest with a constant acceleration g/8. A stone is released
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm