⇦ | ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - Avalanche breakdown is due to
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
- An object is attached to the bottom of a light vertical spring and set vibrating.
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
- Which of the following, is a vector quantity?
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Avalanche breakdown is due to
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
- An object is attached to the bottom of a light vertical spring and set vibrating.
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
- Which of the following, is a vector quantity?
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm