⇦ | ![]() | ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - In R-L-C series circuit, the potential differences across each element is 20 V.
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- The ionization energy of Li⁺⁺ is equal to
- A susceptibility of a certain magnetic material is 400. What is the class
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In R-L-C series circuit, the potential differences across each element is 20 V.
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- The ionization energy of Li⁺⁺ is equal to
- A susceptibility of a certain magnetic material is 400. What is the class
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm