| ⇦ | 
| ⇨ |
The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be
Options
(a) 2 dm³
(b) 3 dm³
(c) 4 dm³
(d) 8 dm³
Correct Answer:
4 dm³
Explanation:
P₁ = P , V₁ = 4 dm³, T₁ = T. P₂ = 2P, V₂ = ?, T₂ = 2T. From gas equation, P₁V₁ / T₁ = P₂V₂ / T₂ ⇒ P * 4 / T = 2P * V / 2T. ⇒ V = 4dm³.
Related Questions: - The main constituent of a natural gas is
- One gram mole of a gas at NTP occupies 22.4 L.This facts was derived from
- Difference in density is the basis of
- Which metal is extracted by complexing with KCN
- Which of othe following is paramagnetic?
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The main constituent of a natural gas is
- One gram mole of a gas at NTP occupies 22.4 L.This facts was derived from
- Difference in density is the basis of
- Which metal is extracted by complexing with KCN
- Which of othe following is paramagnetic?
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply