| ⇦ | 
| ⇨ |
The increasing order of the density of alkali metals
Options
(a) Li < K < Na < Rb < Cs
(b) Li < Na < K < Rb < Cs
(c) Cs < Rb < Na < K < Li
(d) Cs < Rb < K < Na < Li
Correct Answer:
Li < K < Na < Rb < Cs
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - How many moles of lead (II) chloride will be formed from a reaction between
- The gas which combin with haemoglobin to damage its oxygen carrying capacity is
- According to Bohr’s theory, the angular momentum of electron in 5th orbit is
- Which of the esters shown, after reduction with LiAlH₄ and aqueous workup, will
- Chemical bond implies
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many moles of lead (II) chloride will be formed from a reaction between
- The gas which combin with haemoglobin to damage its oxygen carrying capacity is
- According to Bohr’s theory, the angular momentum of electron in 5th orbit is
- Which of the esters shown, after reduction with LiAlH₄ and aqueous workup, will
- Chemical bond implies
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Li se K me K ka volume increase hota hai. Volume increase hone se
K ki density Na se bhi kam ho jati hai ( density =mass \ volume) . For this reason Li < K < Na < Rb < Cs.