| ⇦ |
| ⇨ |
The power obtained in a reactor using U²³⁵ disintegration is 1000 kW. The mass decay of U²³⁵ per hour is
Options
(a) 10 microgram
(b) 20 microgram
(c) 40 microgram
(d) 1 microgram
Correct Answer:
40 microgram
Explanation:
E = mc² m = E / c² so, mass decay per second.
dm/ dt = 1/c² . dE/ dt = 1/c² (Power in watt)
= 1 / (3 x 10⁸)² x 1000 x 10³
and mass decay per hour = dm/ dt x 60 x 60
= 1 / (3 x 10⁸)² x 10⁶ x 3600 = 4 x 10⁻⁸ kg = 40 microgram
Related Questions: - Two particles are oscillating along the same line with the same frequency
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- When an electron beam passes through an electric field they gain kinetic energy.
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- The dimensions of latent heat are
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles are oscillating along the same line with the same frequency
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- When an electron beam passes through an electric field they gain kinetic energy.
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- The dimensions of latent heat are
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply