⇦ | ![]() | ⇨ |
The power obtained in a reactor using U²³⁵ disintegration is 1000 kW. The mass decay of U²³⁵ per hour is
Options
(a) 10 microgram
(b) 20 microgram
(c) 40 microgram
(d) 1 microgram
Correct Answer:
40 microgram
Explanation:
E = mc² m = E / c² so, mass decay per second.
dm/ dt = 1/c² . dE/ dt = 1/c² (Power in watt)
= 1 / (3 x 10⁸)² x 1000 x 10³
and mass decay per hour = dm/ dt x 60 x 60
= 1 / (3 x 10⁸)² x 10⁶ x 3600 = 4 x 10⁻⁸ kg = 40 microgram
Related Questions:
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- Two liquid drops having diameters of 1 cm and 1.5 cm. The ratio of excess
- The Boolean expression P+ P ̅ Q, where P and Q are the inputs of the logic
- An electric motor runs on DC source of emf 200 V and draws a current of 10 A.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply