| ⇦ | 
| ⇨ |
The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
Options
(a) 2
(b) 3/√2
(c) √2
(d) 1/√2
Correct Answer:
3/√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If c is the velocity of light in free space, the time taken by light to travel
- A resistance of 20 ohm is connected to a source of an alternating potential V
- The work done in which of the following processes is equal to the change in internal energy
- Rutherford’s α-scattering experiment concludes that
- Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If c is the velocity of light in free space, the time taken by light to travel
- A resistance of 20 ohm is connected to a source of an alternating potential V
- The work done in which of the following processes is equal to the change in internal energy
- Rutherford’s α-scattering experiment concludes that
- Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply