⇦ | ![]() | ⇨ |
The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
Options
(a) 2
(b) 3/√2
(c) √2
(d) 1/√2
Correct Answer:
3/√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A small signal voltage V(t)=V₀ sin ωt is applied across an ideal capacitor C
- Ohm’s law valid
- An electric dipole of dipole moment p is aligned parallel to a uniform electric field E
- The damping force on an oscillator is directly proportional to the velocity.
- A lens having focal length f and aperture of diameter d forms an image of intensity I
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply