| ⇦ | 
| ⇨ |
The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
Related Questions: - A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- The average power dissipated in a pure inductor is
- In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- The average power dissipated in a pure inductor is
- In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply