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The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons striking the target per second is
Options
(a) 5 x 10¹⁶
(b) 1 x 10¹⁷
(c) 4 x 10¹⁵
(d) 2 x 10¹⁶
Correct Answer:
2 x 10¹⁶
Explanation:
Let n = number of electrons striking per sec.
e = 1.6 × 10⁻¹⁹ = charge on each electron
Charge per second = n × 1.6 × 10⁻¹⁹
Current = n × 1.6 × 10⁻¹⁹
3.2 × 10⁻³ = n × 1.6 × 10⁻¹⁹
n = 3.2 × 10⁻³ / 1.6 × 10⁻¹⁹ = 2 × 10¹⁶
Related Questions: - Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- 180⁰ phase difference is obtained when light ray is reflected from
- The horizontal range of a projectile is 4√3 times the maximum height achieved
- A point charge q is placed at a distance x/2 directly above the centre of a cube
- The near point and far point of a person are 40 cm and 250 cm, respectively.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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