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The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons striking the target per second is
Options
(a) 5 x 10¹⁶
(b) 1 x 10¹⁷
(c) 4 x 10¹⁵
(d) 2 x 10¹⁶
Correct Answer:
2 x 10¹⁶
Explanation:
Let n = number of electrons striking per sec.
e = 1.6 × 10⁻¹⁹ = charge on each electron
Charge per second = n × 1.6 × 10⁻¹⁹
Current = n × 1.6 × 10⁻¹⁹
3.2 × 10⁻³ = n × 1.6 × 10⁻¹⁹
n = 3.2 × 10⁻³ / 1.6 × 10⁻¹⁹ = 2 × 10¹⁶
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space
- The half-life of radioactive element is 600 yr. The fraction of sample
- An alternating electric field, of frequency v, is applied across the dees (radius = R)
- Which series of hydrogen spectrum corresponds to ultraviolet region?
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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