| ⇦ | 
| ⇨ |
The point of suspension λ of a simple pendulum with normal time period T₁ is moving upward according to equation y=kt² where k=1 m/s². If new time period is T² the ratio T₁²/T₂² will be
Options
(a) (2/3)
(b) (5/6)
(c) (6/5)
(d) (3/2)
Correct Answer:
(6/5)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A 1kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed
- If the electric field lines is flowing along axis of a cylinder, then the flux
- Which of the following is suitable for the fusion process?
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply