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The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two tuning forks are sounded together and produce 2 beats per second.
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- In L-C-R series circuit, an alternating emf e and current i are given by the equations
- How much work is required to carry a 6 μC charge from the negative terminal
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Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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