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The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- To what temperature should the hydrogen at room temperature (27°C) be heated at constant
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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